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Re: [xsl] extend an xslt template defined elsewhere?

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It probably wouldn't, but is something I'd rather not see in the source.

Its too bad <xsl:attribute-set> doesn't support xsl:if or xsl:choose.

On 10/19/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> That was one of my caveats that I said at the very beginning. Only
> <xsl:attribute> elements can be children of <xsl:attribute-set>, so you
> can't wrap them in <xsl:if>.
>
> Why would an empty class attribute invalidate your result document?
>
> ~ Scott
>
>
> -----Original Message-----
> From: ettinger@xxxxxxxxx [mailto:ettinger@xxxxxxxxx] On Behalf Of
> Anthony Ettinger
> Sent: Friday, October 19, 2007 6:17 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] extend an xslt template defined elsewhere?
>
> On 10/19/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
>
> > If this IS the case, you can do this:
> >
> > <xsl:import href="docbook.xsl"/>
> > <xsl:attribute-set name="glossdef">
> >   <xsl:attribute name="class">
> >     <xsl:value-of select="@role"/>
> >   </xsl:attribute>
> > </xsl:attribute-set>
> >
>
>
> I still have an empty class attribute in my html output.
>
>
>
>
>
>
>
>
>
> --
> Anthony Ettinger
> Ph: 408-656-2473
> var (bonita, farley) = new Dog;
> farley.barks("very loud");
> bonita.barks("at strangers");
>
> http://chovy.dyndns.org/resume/
> http://utuxia.com/consulting
>
>


-- 
Anthony Ettinger
Ph: 408-656-2473
var (bonita, farley) = new Dog;
farley.barks("very loud");
bonita.barks("at strangers");

http://chovy.dyndns.org/resume/
http://utuxia.com/consulting

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