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John Smith wrote:
xsl:copy copies the current node. xsl:copy-of select="@*" copies any attribute nodes. xsl:apply-templates processes all child nodes.
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Re: [xsl] Output input_xml apart from one tag change?
Subject: Re: [xsl] Output input_xml apart from one tag change? From: Martin Honnen <Martin.Honnen@xxxxxx> Date: Tue, 02 Oct 2007 15:37:07 +0200 |
John Smith wrote:
That works perfectly, thanks. But what actually happens here:
<xsl:copy><xsl:copy-of select="@*"/><xsl:apply-templates/></xsl:copy>
xsl:copy copies the current node. xsl:copy-of select="@*" copies any attribute nodes. xsl:apply-templates processes all child nodes.
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Martin Honnen http://JavaScript.FAQTs.com/
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