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Re: [xsl] XSL: Format date
Subject: Re: [xsl] XSL: Format date
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Sat, 29 Sep 2007 00:28:46 +0200
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Hi HC,
I hope you are using XSLT 2.0 (you didn't specify), though it wouldn't
be hard in XSLT 1.0, it is just so much easier 2.0. Here it goes:
<xsl:sequence select="replace(first/date, '(\d+)\.(\d+)\.(\d+)',
'\2/\1/\3') />
hmm, while writing it, looks pretty obfuscated hehe. Perhaps the XSLT
1.0 way with nested substring-before is clearer after all. An
alternative approach would be to convert it into a date and use
format-date() on it.
Thinking of Larry Wall's: there's more than one way to do it. Though
XSLT is not Perl, it can get close. Here's another method (and I'm sure
there're a thousand more!):
<xsl:value-of select="for $i in (2,1,3) return tokenize(first/date,
'\.')[$i]" separator="/" />
if you need some extra explanation on these ones, I am happy to help you
further. Btw, I personally like that last solution, just happened to
come up like that ;)
Cheers,
-- Abel Braaksma
Chaudhary, Harsh wrote:
Hi,
I am sure this has been discussed to death but I have not been able to
find a good source of info on it.
I have an xml:
<first>
<date>31.12.2006</date>
</first>
I would like to convert it to 12/31/2006.
Is there any built in function for this or is string formatting the way
to go?
Thanks,
HC.
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