Re: [xsl] Getting variable yet most immediate parentNode

try to avoid using name() (for various reasons, it can be unrelaible in
the face of namespaces and can be slow always)

<xsl:template match="option[name(..) = 'questions']">

<xsl:template match="option[parent::questions]">
or more simply
<xsl:template match="questions/option">

David

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