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Hi,
This is what I got for the output (I am actually using XSLT to transform into HTML, so the XML, as described previously, was that input)
The output, oddly, when I used <xsl:value of select="count(title)"/> instead of position() it produced 2 and 1, respectively, but when the <xsl:apply-templates was inserted, it generates output of
When I used the one I posted earlier:
It brings back the same input. However, I wanted the one on the first of the <title> to be something like:
<div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div>
Is there some way I can do this?
Many thanks.
Alice
RE: [xsl] [XSL]Display Different Results Based on Count of NodeSets
Subject: RE: [xsl] [XSL]Display Different Results Based on Count of NodeSets From: Alice Ju-Hsuan Wei <ajwei@xxxxxxxxxxx> Date: Mon, 24 Sep 2007 07:17:59 -0400 |
Hi,
This is what I got for the output (I am actually using XSLT to transform into HTML, so the XML, as described previously, was that input)
The output, oddly, when I used <xsl:value of select="count(title)"/> instead of position() it produced 2 and 1, respectively, but when the <xsl:apply-templates was inserted, it generates output of
<div><p>Tennison, Jeni.</p> <p><i>Beginning XSLT</i>.</p> <p><i>Begining XSLT 2.0</i>.</p></div>
<div><p>Meyer, Eric.</p> <p><i>The Zen of CSS</i>.</p> </div>
When I used the one I posted earlier:
<xsl:template match="title"> <xsl:choose> <xsl:when test="position() ='1'"/> <xsl:otherwise> <p> <xsl:apply-templates/>
</p> </xsl:otherwise> </xsl:choose> </xsl:template>
It brings back the same input. However, I wanted the one on the first of the <title> to be something like:
<div><p>Tennison, Jeni. <i>Beginning XSLT</i>.</p> <p><i>Begining XSLT 2.0</i>.</p></div>
<div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div>
Is there some way I can do this?
Many thanks.
Alice
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