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Andrew Welch wrote:
Hi David, thanks for your response. Surely that adds to clarity (and iirc, Michael Kay often tried to emphasize the use of the 'as' clause to prevent the document node from being created). But root() never seems to fail: in your example, that means that the result is a sequence of two elements with each having a root equal to self::node()? And both, I guess, not being siblings from one another?
Re: [xsl] Trying to understand root-less or document-node-less nodes
Subject: Re: [xsl] Trying to understand root-less or document-node-less nodes From: Abel Braaksma <abel.online@xxxxxxxxx> Date: Mon, 17 Sep 2007 13:17:30 +0200 |
Andrew Welch wrote:
What you're describing is the same as typing the variable as="element()" eg:
<xsl:variable name="root" as="element()+"> <test1 /> <test2 /> </xsl:variable>
By adding as="element()+" the variable goes from a root with two child elements that are siblings (eg to access <test1/> use $root/test1) to a sequence of elements with no root and that aren't siblings (to access <test1/> use $root[1])
Hi David, thanks for your response. Surely that adds to clarity (and iirc, Michael Kay often tried to emphasize the use of the 'as' clause to prevent the document node from being created). But root() never seems to fail: in your example, that means that the result is a sequence of two elements with each having a root equal to self::node()? And both, I guess, not being siblings from one another?
Cheers, -- Abel Braaksma
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