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Re: [xsl] passing xml strings to xslt using saxon in java
Subject: Re: [xsl] passing xml strings to xslt using saxon in java
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Sun, 16 Sep 2007 17:42:30 +0200
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The direct answer to your question is: just pass in the string that
contains the contents of the xml.
But I assume that after that, you want to create XML from this string
and you want to process it (otherwise, why would you ask how to pass in
a string? I am sure you know how to do that). Simply use the saxon:parse
and/or saxon:serialize extension functions. You can find the details on
how to use them on the Saxon website (the first parses an xml string and
constructs a node set, the second does the opposite and returns a string
equal to what would be produced through normal output processing)
Cheers,
-- Abel Braaksma
PS: note that there is no recovery when the string that is passed in is
not well-formed xml!
John Smith wrote:
Hello,
I have a xslt which needs to use 2 xml files, the first one is not
actually a file but an xml formatted string and the second one is an
xml file.
So I want:
xmlString + rules.xml + XSL.xslt = Result.xml
I have tested the scenario with the xsl file referencing the xml files as:
<xsl:variable name="myrules" select="document('myrules.xml')"/>
<xsl:variable name="xmlstring" select="document('myXmlString.xml')"/>
and then created a resulting xml file. However instead of referencing
a file I want to dynamically pass an xmlString to it. I am using
Java+Saxon, is there a way around this? or any alternative methods to
address this problem?
Many thanks,
J
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