Re: [xsl] Identical entries in different input documents should appear in the output document only once

> That's all ... Wow :-)

it's a bit more than you need though:-)


   <xsl:for-each select="current-group()[1]"> <!-- In my case all blocks

is (always) the same thing as

   <xsl:for-each select="."> <!-- In my case all blocks

which is always the same thing as

     <!-- In my case all blocks

so the code can be


<xsl:for-each-group select="document($allFiles)//root/block"
group-by="idTag">
 <!-- In my case all blocks
from different files are really identical -->
      <xsl:call-template name="makeMyTransformationOnTheBlock"/>
</xsl:for-each-group>


If <root> is always the top level element, using /root/block instead of
//root/block would save the processor a lot of work as // implies
(except when Michael optimizes it away) a full search to arbitrary depth
of each document to find all elements of that name.


David

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