[xsl] Finding the current node type

Thanks Guys

In my application, I will only need to process a few hundred nodes and
about 20-30 of the type where I need to use the choose statement.

I went with the <xsl:if test=self::speaker> option as I still use the
namespace (e.g. <xsl:if test=self::abc:speaker>). Whereas localname
returned the node name without the ns prefix

Thanks for the help

Regards

mark