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Hi all,
I have written a stylesheet that selects the deepest node when there is a match with a keyword. I want to expand my stylesheet so that it also selects the median. I need to count the number of nodes for the deepest node. I am using Saxon's function saxon:path() to give me the absolute path.
I use xsl:sort and position() = 1 to select the deepest node. I know you can use the function count() to count the number of nodes. I want to test if a path contains at least 4 nodes while I am at the deepest node. I am trying count(saxon:path()), but that clearly is not working. Anyone know how I can pull off this trick?
[xsl] Selecting Median of Root to Deepest node
Subject: [xsl] Selecting Median of Root to Deepest node From: "J. Zhang" <j.zhang@xxxxxx> Date: Wed, 01 Aug 2007 12:06:38 +0200 |
Hi all,
I have written a stylesheet that selects the deepest node when there is a match with a keyword. I want to expand my stylesheet so that it also selects the median. I need to count the number of nodes for the deepest node. I am using Saxon's function saxon:path() to give me the absolute path.
I use xsl:sort and position() = 1 to select the deepest node. I know you can use the function count() to count the number of nodes. I want to test if a path contains at least 4 nodes while I am at the deepest node. I am trying count(saxon:path()), but that clearly is not working. Anyone know how I can pull off this trick?
Thanks jz
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