[xsl] Finding the current node type

Hi Kamal

Thanks for the tip. It worked but for some reason the namespace prefix
is not part of the node name:

For example, I have <abc:code>1234</abc:code>

Local-name returns "code"

I can work without the namespace prefix, just struck me as being a bit
strange.


>If I understand what you are trying to do, you could use local-name().
>This will give you the name of the node.

Regards

Mark