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Re: [xsl] listing elements based on 2 conditions

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Shouldn't this work..

<xsl:for-each select="element[type = 'business']">
 <xsl:if test="position() &lt; 6">
   <xsl:copy-of select="name" />
 </xsl:if>
</xsl:for-each>

On 7/5/07, Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx> wrote:

Hi, i'm having an aparenty simple problem but I can't find a convenient solution to it.
I have a list like this:

<element>
   <name>name1</name
   <type>bussines</type>
</element>

<element>

<name>name2</name

<type>sport</type>

</element>

<element>

<name>name3</name

<type>bussines</type>

</element>

I need to display the name of the first 5 elements that have the type bussines.
First I tried using if test="position() < 6 and type="bussines" but this only displays the names from the first 5 news that are type bussines when I actually need the first 5 of type bussines from the whole list. anyone knows an easy way to do this ( in xslt 1.0 )??? 10x

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Regards,
Mukul Gandhi

http://gandhimukul.tripod.com/

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