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Re: [xsl] Removing an XML Attribute


Subject: Re: [xsl] Removing an XML Attribute
From: Tony Graham <Tony.Graham@xxxxxxxxxxxxxxxxxxxxxx>
Date: Thu, 05 Jul 2007 00:11:40 +0100

On Wed, Jul 04 2007 19:10:22 +0100, Shaun.McDonald@xxxxxxxxxxx wrote:
> I came up with something that appears to work, only I'm not sure if
> there is a caveat to doing it this way.
>
> Since I'm transforming almost 100 files, I want to make sure nothing
> bites me in the rear.
>
> Using XSLT 2.0, Saxon 8.8
>
> <xsl:template match="*">
>   <xsl:copy>
>     <xsl:choose>
>      <xsl:when test="not(@change)">
>        <xsl:copy-of select="@* "/>
>      </xsl:when>
>      <xsl:otherwise/>
>    </xsl:choose>
>    <xsl:apply-templates/>
>  </xsl:copy>
> </xsl:template>
>
> I'm still spot-checking the files, but so far it seems to have removed
> the @change attribute only, which is my desired output.

That would appear to be because @change is the only attribute on that
particular element.

Your template copies all attributes if @change is not present, and
copies no attributes if it is present.

(If you have just one test, you can use xsl:if instead of xsl:choose,
and when you do use xsl:choose, the xsl:otherwise is optional.)

Try just:

   <xsl:copy-of select="@*[not(self::change)]"/>

Regards,


Tony Graham.
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