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Re: [xsl] call-template error

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In addition to the explanation of Dr. Kay, see:

http://fxsl:sf.net

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Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
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To invent, you need a good imagination and a pile of junk
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You've achieved success in your field when you don't know whether what
you're doing is work or play

On 5/28/07, Vaduvoiu Tiberiu <vaduvoiutibi@xxxxxxxxx> wrote:

On my site I have a couple of categories/menus. Each time you're in a category it loads a different template(content)
I have a parameter $menu which has the value of the name of the menu you are at on the site. So until now I had something like this:

<xsl:if test="$menu= sport">
<xsl:call-template name="toolbox_sport"></xsl:call-template>
</xsl:if>
<xsl:if test="$menu= 'news">
<xsl:call-template name="toolbox_news"></xsl:call-template>
</xsl:if>
<xsl:if test="$menu= recent">
<xsl:call-template name="toolbox_recent"></xsl:call-template>
</xsl:if>
<xsl:if test="$menu= test">
<xsl:call-template name="toolbox_test"></xsl:call-template>
</xsl:if>

like this, it works. But then I though of making it more simple like this:

<xsl:call-template name="toolbox_$menu"></xsl:call-template> so basically it should only loads the template of the selected menu. Thing is it doesn't work..I get java.util.EmptyStackException:

I also tried creating a variable
<xsl:variable name="tool">toolbox_<xsl:value-of select="$menu"/></xsl:variable>
and then calling the template with the name="$tool"..also doesn't work. So why doesn't he load it?? 10x

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