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RE: [xsl] Extract input filename


Subject: RE: [xsl] Extract input filename
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Thu, 17 May 2007 11:10:14 +0100

Well, that probably means you changed the parameter name from "meta" to
"data" in one place but not in the other place. 

> -----Original Message-----
> From: J. S. Rawat [mailto:jrawat@xxxxxxxxxxxxxx] 
> Sent: 17 May 2007 10:39
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] Extract input filename
> 
> New error has been introduced!!
> error
> XTDE0050: No value supplied for required parameter data
> 
> At 10:26 AM 5/17/2007 +0100, you wrote:
> >The namespace prefix xs is the conventional prefix for 
> >http://www.w3.org/2001/XMLSchema which is where the data 
> types are defined.
> >You don't have to declare the data types of your variables and 
> >parameters in XSLT 2.0 but it's good practice and I do it as 
> a matter of habit.
> >
> >Michael Kay
> >http://www.saxonica.com/
> >
> > > -----Original Message-----
> > > From: J. S. Rawat [mailto:jrawat@xxxxxxxxxxxxxx]
> > > Sent: 17 May 2007 09:44
> > > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > > Subject: RE: [xsl] Extract input filename
> > >
> > > Thanks for the prompt reply. Would you please let me know 
> about the 
> > > namesspace value of prefix {xs} as an error is throughing while 
> > > converting.
> > >
> > > Error
> > > undeclared namespace prefix {xs}
> > >
> > > At 08:46 AM 5/17/2007 +0100, you wrote:
> > >
> > > >1. Change this:
> > > >
> > > ><xsl:variable name="filename" 
> select="document('input_meta.xml')" 
> > > >/>
> > > >
> > > >to this:
> > > >
> > > ><xsl:param name="meta" as="xs:string" required="yes"/> 
> > > ><xsl:variable name="filename" select="document($meta)" />
> > > >
> > > >(you might also like to change the name of the variable 
> filename, 
> > > >as it's a misleading name)
> > > >
> > > >2. Change your command line to
> > > >
> > > >java -jar saxon8.jar input.xml x.xsl meta=input_meta.xml >c.xml
> > > >
> > > >Michael Kay
> > > >http://www.saxonica.com/
> > > >
> > > >
> > > > > I have no idea about to extract input filename by passing
> > > argument
> > > > > in command line. In the below examples, I don't want 
> to hardcode 
> > > > > "input_meta.xml".
> > > > >
> > > > > Input files
> > > > > 1. input.xml
> > > > > 2. input_meta.xml
> > > > >
> > > > > command line
> > > > > java -jar saxon8.jar input.xml x.xsl >c.xml
> > > > >
> > > > > Stylesheet
> > > > > <xsl:variable name="filename"
> > > select="document('input_meta.xml')" />
> > > > > <xsl:template match="/">
> > > > >       <doi>
> > > > >        <xsl:copy-of select="$filename/doi/text()" />
> > > > >       </doi>
> > > > > </xsl:template>
> > > > >
> > > > > Thanks in advance.
> > > > > JSR


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