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Re: [xsl] variable in xsl:template match
Subject: Re: [xsl] variable in xsl:template match
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 26 Apr 2007 16:52:58 +0200
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Garvin Riensche wrote:
Great! Thanks to you an Ronan for the quick answer!
/root/node()[name() = $target]/child
Be aware of namespaces... You may want to use local-name() or some other
method, as in my previous post. Also, you need XSLT 2.0, but that was
already explained to you.
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