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RE: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?
Subject: RE: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Mon, 5 Mar 2007 09:23:24 -0000
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> Hi,
> I use <xsl:copy-of select="./*"/> to select child elements
> of a node which passes <xsl:when>. However copy-of is
> inserting
> xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance with
> each child element it selects.
In XSLT 2.0 you can copy an element without copying its namespaces using the
copy-namespaces="no" attribute.
In XSLT 1.0 the answer is no. xsl:copy-of copies a tree unchanged, which
includes its namespace nodes (remember that in the data model, an element
has namespace nodes corresponding to all in-scope namespaces, including
those declared on ancestor elements). You only remedy is not to use
xsl:copy-of, but to do a manual copy using a modified identity template:
<xsl:template match="*">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select="@*"/>
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
Michael Kay
http://www.saxonica.com/
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