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where digit is the distance from the first prevoius <a>.
I use XSLT 2.0 with Saxon.
Thanks in advance.
~alex
[xsl] how to know distance between two sibling nodes
Subject: [xsl] how to know distance between two sibling nodes From: "alex v." <alex.vett@xxxxxxxxx> Date: Wed, 14 Feb 2007 11:17:13 +0100 |
Hi all, I would like to know distance between two sibling nodes. One solution maybe is to count siblings between the two nodes. So, I have a sequence of sibling node, for example:
<a> <b> <c> <a> <b> <c> <c>
and when I match element <c> I need to know the number of preceding-sibling only until the first previous element <a>, also it is:
<a> <b> <c> = 2 <a> <c> = 1 <c> = 2
where digit is the distance from the first prevoius <a>.
I think that count(preceding-sibling::a[1]) is the solution, but it seems don't work for me. Why this?
I use XSLT 2.0 with Saxon.
Thanks in advance.
~alex
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