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Re: [xsl] mod position() tests positive all of the time

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Hi Allen,

It is hard to answer your question without knowing the input. In a subsequent post, please add a minimum working set of your data that applies to your stylesheet. In addition, it helps a great deal if you show exactly how the unwanted and the wanted output looks like (and I wouldn't object to indentation for readability in xml and xslt). I added some notes nevertheless, see below.

Cheers,
-- Abel Braaksma
  http://www.nuntia.nl

Allen Jones wrote:

<xsl:call-template name="results"/>

Why did you choose to use call-template? Using apply-template and template matches is likely much easier.

<xsl:template name="results">
<table>
<xsl:for-each
select="insightResponse/searchResponse/collectionResultSet/object/thumbnail[position()
mod 5 = 1]">

What this does highly depends on your input. For instance, if you have a set of "object" nodes, and each has one "thumbnail" node, then this for-each will select all of them (as postion() is always for each first thumbnail node under object). Depending on your input, you may want to write this a little different for readability, but as far as I can tell, this code is not wrong per se.

<tr>
<xsl:apply-templates select=". | following-sibling::thumbnail[position()
&lt; 5]" />

This <tr> indeed will always show up, when you have at least one thumbnail in the xpath of the for-each. But I'm not certain I've understood your problem well enough. Next you apply the templates to the current thumbnail node and its first four siblings. Is this part working correctly?

</tr>
</xsl:for-each>
</table>
</xsl:template>

<xsl:template match="thumbnail">
<td align="center"><img src="{@URL}" /><br />
<xsl:for-each select="label"><xsl:value-of select="."/><br
/></xsl:for-each>
</td>
</xsl:template>

Here you appear to output a bunch of values of label nodes. Is this part correctly working?

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