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Re: [xsl] Grouping using concatenated key
Subject: Re: [xsl] Grouping using concatenated key From: jmcreynolds@xxxxxxxxxxxxxx Date: Mon, 11 Dec 2006 10:36:21 -0600 (CST) |
David, Thanks again for your help. It does help if the person seeking help follows the rules, no? :) Sorry for not adhering to the guidelines of the group... Here is the abbreviated XML representation that I am working with: <NewDataset> <BillDetail> <OBLIGATION_ID>2750</OBLIGATION_ID> <PHONE_NUMBER>1234567890</PHONE_NUMBER> </BillDetail> <BillDetail> <OBLIGATION_ID>2750</OBLIGATION_ID> <PHONE_NUMBER>9876543210</PHONE_NUMBER> </BillDetail> <BillDetail> <OBLIGATION_ID>3940</OBLIGATION_ID> <PHONE_NUMBER>1234567890</PHONE_NUMBER> </BillDetail> </NewDataset> Does this clarify things? Many thanks (yet again!), JOHN > > <xsl:template match="/"> > > so you are at the document root. in a well formed document there can > only be exactly one element child of / so > > <xsl:for-each > select="BillDetail[ > > you are for-eaching over at one element so grouping is not going to be > very interesting. > > i suspect that you have multiple BillDetail elements and they have a > parent element, in which case you should (or could) put the grouping > code in the template for that element. > > Please see the posting guidelines at the list home page, which suggests > posting _complete_ _small_ examples. Your posted input was quite large > but has lots of detail not relevant to the problem (<FROM_CITY> and > friends) but isn't a well formed document as the two elements have no > parent element so peopel can't post code that actually runs on your > example. > > David
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