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RE: [xsl] new bie question
Subject: RE: [xsl] new bie question From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 5 Dec 2006 02:55:33 -0000 |
In 2.0: select="document(document('index.xml')/protest/package/name/concat(., '.xml'))"> In 1.0: <xsl:for-each select="document('index.xml')/protest/package/name"> <xsl:for-each select="document(concat(., '.xml'))"> .... Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: chun ji [mailto:cji_work@xxxxxxxxx] > Sent: 04 December 2006 23:27 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] new bie question > > I have an index.xml file, which reads as: > " > -<?xml version="1.0" encoding="ISO-8859-1" ?> > -<?xml-stylesheet href="rules.xsl" type="text/xsl"?> -<protest> > -<package> > -<name>billing</name> > -</package> > -<package> > -<name>timecard</name> > -</package> > -</protest> > ". > There is a group of child xml files that associated with each > "/protest/package/name", such as "billing.xml", "timecard.xml". > > Now I have soming in my XSL file that tries to open all these > CHILD xml files, " <xsl:for-each > select="document(document('index.xml')/protest/package/name)"> > . > </xsl:for-each> > " > which fails, because I did not give ".xml" for each > child xml. > > Does someone know the format to do it ? > > > thanks a lot > > > cji > > > > ______________________________________________________________ > ______________________ > Yahoo! Music Unlimited > Access over 1 million songs. > http://music.yahoo.com/unlimited
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