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RE: [xsl] Is it possible to create xsl:sort from input parameters using XSLT 2.0 (Saxon)?
Subject: RE: [xsl] Is it possible to create xsl:sort from input parameters using XSLT 2.0 (Saxon)? From: Nick Glenister <NGlenister@xxxxxxxxxxxxxxxx> Date: Thu, 2 Nov 2006 12:18:59 -0000 |
Hi, Sorry to bring this problem up again but I'm still having problems with getting this sort to work. To recap I have an XSLT that transforms XML into ASP.NET which shows a list of financial products and some basic details. In order to sort these products I am passing in a second XML document node in the following format: <SortFields> <SortField> <Sort>lendername</Sort> <Order>ascending</Order> <DataType>text</DataType> <CaseOrder>lower-first</CaseOrder> </SortField> <SortField> <Sort>lenderid</Sort> <Order>ascending</Order> <DataType>text</DataType> <CaseOrder>lower-first</CaseOrder> </SortField> <SortField> <Sort>productid</Sort> <Order>ascending</Order> <DataType>text</DataType> <CaseOrder>lower-first</CaseOrder> </SortField> </SortFields> This xml is passed into this parameter: <xsl:param name="sortField" as="document-node()"/> This XML document defines three levels of sorting and is applied to the primary XML using the following XSLT (separated over several lines for clarity in the e-mail. There is one of these sort elements for each of the three sorts): <xsl:sort select="$sortField/SortFields/SortField[1]/Sort" order="{$sortField/SortFields/SortField[1]/Order}" data-type="{$sortField/SortFields/SortField[1]/DataType}" case-order="{$sortField/SortFields/SortField[1]/CaseOrder}" /> The problem is that it doesn't work. There are no errors but the sorting does not occur. Doing a <xsl:value-of select="$sortField/SortFields/SortField[1]/Sort"/> brings through the string "lendername" I just can't see why the sorting is not working. Hard coding the value "lendername" sorts the output perfectly so I'm sure that XSLT is operating ok in all other repects.
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