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Re: [xsl] For-each-group problem

Subject: Re: [xsl] For-each-group problem
From: "andrew welch" <andrew.j.welch@xxxxxxxxx>
Date: Mon, 2 Oct 2006 16:40:07 +0100
On 10/2/06, Mario Madunic <hajduk@xxxxxxxx> wrote:
Can't seem to get the results I want using for-each-group

Using Saxon 8 and XSLT 2

Sample doc

<root>
  <body>
    <heading>
    <p></p>
    <p></p>

    <li></li>
    <div>
      <p></p>
      <p></p>
    </div>

    <li></li>
    <div>
      <p></p>
      <p></p>
      <p></p>
      <p></p>
    </div>

    <li></li>
    <div>
      <p></p>
      <p></p>
    </div>

    <p></p>
    <p></p>
    <footer></footer>
  <body>
</root>

I want it to look like the following

<root>
  <body>
    <heading>
    <p></p>
    <p></p>

    <li>
      <div>
        <p></p>
        <p></p>
      </div>
    </li>

    <li>
      <div>
        <p></p>
        <p></p>
        <p></p>
        <p></p>
      </div>
    </li>

    <li>
      <div>
        <p></p>
        <p></p>
      </div>
    </li>

    <p></p>
    <p></p>
    <footer></footer>
  <body>
</root>

I've followed the example in MK's XSLT 2 book page # 297 and haven't achieved
the same results. I have a bunch of elements that this must be done to.

Firstly your samples aren't well-formed XML, which doesn't help. However...

you don't need grouping here, just a variation of the identity transform:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@*|node()">
	<xsl:copy>
		<xsl:apply-templates select="@*|node()"/>
	</xsl:copy>
</xsl:template>

<xsl:template match="heading">
	<xsl:copy>
		<xsl:apply-templates select="*[not(self::div)]"/>
	</xsl:copy>
</xsl:template>

<xsl:template match="li">
	<xsl:copy>
		<xsl:apply-templates select="following-sibling::*[1][self::div]"/>
	</xsl:copy>
</xsl:template>
</xsl:stylesheet>

produces:

<root>
	<body>
		<heading>
			<p/>
			<p/>
			<li>
				<div>
					<p/>
					<p/>
				</div>
			</li>
			<li>
				<div>
					<p/>
					<p/>
					<p/>
					<p/>
				</div>
			</li>
			<li>
				<div>
					<p/>
					<p/>
				</div>
			</li>
			<p/>
			<p/>
		</heading>
		<footer/>
	</body>
</root>

cheers
andrew

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[xsl] For-each-group problem, Mario Madunic Thread Re: [xsl] For-each-group problem, Mukul Gandhi
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