Re: [xsl] String Replacement in XML using XSLT

Subject: Re: [xsl] String Replacement in XML using XSLT
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Mon, 25 Sep 2006 20:48:59 +0200

Abel Braaksma wrote:

       <xsl:for-each select="tokenize(., '\[|\]')">
       </xsl:for-each>
For XSLT-1 remember to use the exslt:node-set extension

Sorry, no tokenize() function in XPath 1.0.But you can use the contains() suggestion from Mukul.

Also, my apologies for the ugly <xsl:for-each>, that can be done much neater, and even tokenize() is not the best choice I think, but I just wanted to make the point of making your template more readable with an extra step as a tree in a variable.

-- Abel

Current Thread
Re: [xsl] String Replacement in XML using XSLT, (continued) Abel Braaksma - Mon, 25 Sep 2006 20:00:09 +0200 Florent Georges - Mon, 25 Sep 2006 20:10:59 +0200 (CEST) Dimitre Novatchev - Mon, 25 Sep 2006 11:22:04 -0700 Abel Braaksma - Mon, 25 Sep 2006 20:41:43 +0200 Abel Braaksma - Mon, 25 Sep 2006 20:48:59 +0200 <= James Fuller - Mon, 25 Sep 2006 20:39:02 +0200

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Re: [xsl] String Replacement in XML using XSLT