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RE: [xsl] Transform xml without copying one element.
Subject: RE: [xsl] Transform xml without copying one element. From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Tue, 22 Aug 2006 08:31:48 +0100 |
You haven't provided any evidence that there is an element called "variable" in your source document. My guess is that the element you think is called "variable" is in a namespace (which means in effect that it's actually called something else). Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Nishi Bhonsle [mailto:nishiandprafull@xxxxxxxxx] > Sent: 21 August 2006 23:06 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Transform xml without copying one element. > > Hi: > I have the following xslt to transform an xml into another > xml doc such that the first template copies the current node > and attributes and the second one should not copy any > variable elements, but this is not working and the output is > same as input. > > Can you tell me what I am missing here? > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> > <xsl:output method="xml" version="1.0" encoding="UTF-8" > indent="yes"/> <xsl:template match="@*|node()"> > <xsl:copy> > <xsl:apply-templates select="@*|node()"/> > </xsl:copy> > </xsl:template> > <xsl:template match="variable"/> > </xsl:stylesheet> > > > Thanks!
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