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RE: [xsl] populating table with sorted elements
Subject: RE: [xsl] populating table with sorted elements|
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Sun, 30 Jul 2006 09:19:26 +0100
I think this requires two passes: first sorting, then grouping. So it should
be no problem if you are using XSLT 2.0, or XSLT 1.0 with the node-set()
extension. With plain XSLT 1.0 it may be difficult to achieve in a single
> -----Original Message-----
> From: Christian Marc Schmidt [mailto:christianmarc@xxxxxxxxx]
> Sent: 29 July 2006 15:43
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] populating table with sorted elements
> I am a newcomer to XML/XSLT and am struggling with a bit of
> code in which I am attempting to populate a six-column table,
> while allowing an xsl:sort.
> Here is a section of my current code:
> <?xml version="1.0" encoding="utf-8"?>
> <xsl:stylesheet version="1.0"
> <table width="970" border="0" cellspacing="0" cellpadding="0">
> <xsl:for-each select="xml/work/*[position() mod 6 = 1]">
> select=".|following-sibling::*[position() < 6]" />
> The XML structure I've set up looks like this:
> How would I go about adding sort functionality? It seems like
> it would be easy enough, yet all of my attempts so far have failed...
> Any suggestions would be much appreciated!