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Re: [xsl] [XSLT2] Some common, generic grouping problems
Subject: Re: [xsl] [XSLT2] Some common, generic grouping problems
From: "andrew welch" <andrew.j.welch@xxxxxxxxx>
Date: Fri, 30 Jun 2006 10:31:25 +0100
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On 6/30/06, David Carlisle <davidc@xxxxxxxxx> wrote:
oops I got the first one wrong, still in some places in the world it's
not midnight,someone else can fix it before I wake up:-)
This one solves the first one:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes"/>
<xsl:template match="root">
<root>
<xsl:for-each-group select="*" group-starting-with="*[@color='dark-red']">
<xsl:choose>
<xsl:when test="self::*[@color='dark-red']">
<xsl:for-each-group select="current-group()"
group-ending-with="*[@color='light-red']">
<xsl:choose>
<xsl:when test="current-group()[last()][self::*[@color='light-red']]">
<red>
<xsl:copy-of select="current-group()"/>
</red>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="."/>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each-group>
</root>
</xsl:template>
</xsl:stylesheet>
A pair of nested for-each-groups, gives this result:
<root>
<arbitrary/>
<red>
<elem color="dark-red"/>
<elem color="red"/>
<arbitrary color="none"/>
<elem color="red"/>
<elem color="light-red"/>
</red>
<arbitrary/>
</root>
cheers
andrew
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