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Re: [xsl] constructing a "variable" select argument
Subject: Re: [xsl] constructing a "variable" select argument
From: "Tracey Zellmann" <tracey.zellmann@xxxxxxxxxxx>
Date: Mon, 27 Feb 2006 16:10:36 -0500
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Yes!!
Thank you, Florent and MK.
This will probably simplify my stylesheet by at least a factor of 10.
It is a gotcha.
There is one remaining wrinkle I could use you help with.
I have this statement:
<xsl:copy-of select="/Report/TrackT1/Position[@position='Left
Front']/MCHistogram[@id='1']/svg:svg"/>
The position and id attributes can change, and I can handle that as in the
earlier case.
However, the TrackT1 part of the expression can also change - to TrackT2,
TrackT3, Track5-18, etc, taking on various values.
Assuming I bring a parameter into the template, and possibly use
concatenation functions, how can I establish the right value in the middle
of the XPath expression?
----- Original Message -----
From: "Florent Georges" <darkman_spam@xxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Monday, February 27, 2006 2:29 PM
Subject: Re: [xsl] constructing a "variable" select argument
Tracey Zellmann wrote:
However, this does not:
after calling the template with
<xsl:with-param name="track" select="T1"/>
You're selecting here element nodes that are childs of the context
node and whose name is 'T1'. But I wonder if you don't want the string
'T1' instead:
<xsl:with-param name="track" select="'T1'"/>
(note the additional quotes).
Regards,
--drkm
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