[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

Re: [xsl] Printing all child bachelor nodes

---

---

Thanks Andrew, that was spot on!

Cheers.

Dougal.

Douglas F Shearer
dougal.s@xxxxxxxxx
http://douglasfshearer.dyndns.org

On 9 Feb 2006, at 15:28, andrew welch wrote:

On 2/9/06, Douglas F Shearer <dougal.s@xxxxxxxxx> wrote:

Hi there.

  I have the following snippet of XML and would like to extract the
data given below using XSL...

********** XML ************
<features>
<pool length="30" max-depth="160" min-depth="30" indoor="false"/>
<DVD/>
<beds twin="2" sofa-bed="1"/>
</features>

******** REQUIRED OUTPUT ******
pool: length: 30, max-depth:160, min-depth:30, indoor: false.
DVD.
beds: twin:2, sofa-bed:1

**************************************

  The main issue I am having is that the nodes themselves change
(microwave instead of DVD etc). Basically I want to print out all of
the elements within the features element, and their associated
attributes.

<xsl:template match="features/*">
	<xsl:value-of select="local-name()"/>
	<xsl:for-each select="@*">
		<xsl:value-of select="concat(' ', name(), ':', .)"/>
		<xsl:if test="position() != last()">,</xsl:if>
	</xsl:for-each>
	<xsl:text>.</xsl:text>
</xsl:template>

Did you really want text output?  If so you will need to add CRs in
there, but I'm guess you'll be using HTML.  Also, beds didn't end with
a . which I'm also assuming was a typo.

cheers
andrew

---