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Re: [xsl] Automatically generate xpath

Subject: Re: [xsl] Automatically generate xpath
From: David Carlisle <davidc@xxxxxxxxx>
Date: Tue, 31 Jan 2006 00:48:20 GMT

>You showed me how to use union for two xpaths but how would I remove a node 
> from a xpath?

you dont want to remove nodes from a xpath (which is an expression) but
from a node set (which is a value). So you are asking for set
difference: given two node sets $a and $b generate a set of nodes in $a
but not $b.

As I think someone showed earlier, in XPath2 this is

$a except $b

in XPath1 set difference isn't a standard operator but it's available
using the standard idiom:

$a[count(.|$b)!=count($b)]

David

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Current Thread
[xsl] Automatically generate xpath Liron - 30 Jan 2006 22:15:36 -0000 Jay Bryant - 30 Jan 2006 22:57:24 -0000 David Carlisle - 30 Jan 2006 23:02:08 -0000 Liron - 30 Jan 2006 23:51:52 -0000 David Carlisle - 31 Jan 2006 01:12:55 -0000 <= Liron - 31 Jan 2006 01:42:06 -0000 <Possible follow-ups> Liron - 30 Jan 2006 22:52:37 -0000

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