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RE: [xsl] Natural Sort

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> The first way would also work in XSLT1, the second way uses xpath2
> regexp to sort media1 as media01.

It only works if all the numeric parts are one or two digits.

I can't think of an easy way of generalizing it, however.

Michael Kay
http://www.saxonica.com/


> 
> David
> 
>  <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
> version="2.0">
> <xsl:output indent="yes" omit-xml-declaration="yes"/>
> 
> <xsl:template match="x">
> <x>
>   <a>
>     <xsl:for-each select="server">
>       <xsl:sort
> 	  select="translate(substring-before(@dn, '.'),'0123456789','')"
> 	  data-type="text"
> 	  order="ascending"/>
>       <xsl:sort
> 	  select="translate(substring-before(@dn, 
> '.'),'abcdefghijklmnopqrstuvwxyz','')"
> 	  data-type="number"
> 	  order="ascending"/>
>       <xsl:copy-of select="."/>
>     </xsl:for-each>
>   </a>
>   <b>
>     <xsl:for-each select="server">
>       <xsl:sort 
> select="replace(@dn,'([^0-9])([0-9])([^0-9])','$10$2$3')"/>
>       <xsl:copy-of select="."/>
>     </xsl:for-each>
>   </b>
> </x>
> </xsl:template>
> 
>  
> </xsl:stylesheet>
> 
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