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Re: [xsl] XSL formatting
Subject: Re: [xsl] XSL formatting
From: George Cristian Bina <george@xxxxxxxxxxxxx>
Date: Fri, 23 Dec 2005 11:44:55 +0200
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Hi,
Adding an additional for-each that will iterate on the img elements from
the redundant element that do not have a corresponding img in missing
should do it:
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/imgBook">
<html>
<head>
<title>Sample</title>
</head>
<body>
<table border="1">
<tr>
<td>missing</td>
<td>redundant</td>
</tr>
<xsl:for-each select="missing/img">
<xsl:variable name="pos" select="position()"/>
<tr>
<td>
<xsl:value-of select="@name"/>
</td>
<td>
<xsl:value-of select="../../redundant/img[$pos]/@name"/>
</td>
</tr>
</xsl:for-each>
<xsl:variable name="mc" select="count(missing/img)"/>
<xsl:for-each select="redundant/img[position()>$mc]">
<tr>
<td/>
<td>
<xsl:value-of select="@name"/>
</td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:transform>
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com
Shailesh Shinde wrote:
Hi,
Same number of images are not there in both missing and redundant.
Thanks,
Shailesh
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