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Hi Arun,
Why do you need the id to contain its parents id as well?
You have a function, generate-id(), which generates a unique id on a node.
If you need an id like what you state, you will need to do something like this (a variation of identity template):
<xsl:template match="*">
<xsl:variable name="special-id">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="generate-id(.)"/>
</xsl:for-each>
</xsl:variable>
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:attribute name="ID"><xsl:value-of select="$special-id"/></xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Is the above what you need?
RE: [xsl] Generating Unique ID
Subject: RE: [xsl] Generating Unique ID From: "Ragulf Pickaxe" <ragulf.pickaxe@xxxxxxxxxxx> Date: Tue, 06 Dec 2005 09:35:23 +0100 |
Hi Arun,
Why do you need the id to contain its parents id as well?
You have a function, generate-id(), which generates a unique id on a node.
If you need an id like what you state, you will need to do something like this (a variation of identity template):
<xsl:template match="*">
<xsl:variable name="special-id">
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="generate-id(.)"/>
</xsl:for-each>
</xsl:variable>
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:attribute name="ID"><xsl:value-of select="$special-id"/></xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
Is the above what you need?
Regards, Ragulf Pickaxe :-)
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