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Re: [xsl] Exclude by Sibling Condition
Subject: Re: [xsl] Exclude by Sibling Condition From: "Jay Bryant" <jay@xxxxxxxxxxxx> Date: Thu, 1 Dec 2005 20:07:27 -0600 |
Hi, Mike, That's a question to which you can find an answer in Dave Pawson's FAQ at http://www.dpawson.co.uk/xsl/sect2/N2696.html In your case, something like the following will do the trick: <xsl:template match="page[not(@tab=following::page/@tab)]"> <!-- Process the page nodes with unique values for the tab attribute here --> </xsl:template> You can do the same trick in the select attributes of apply-templates or for-each instructions, too, depending on exactly what you need to do. Jay Bryant Bryant Communication Services ----- Original Message ----- From: "Michael B Allen" <mba2000@xxxxxxxxxx> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> Sent: Thursday, December 01, 2005 3:53 PM Subject: [xsl] Exclude by Sibling Condition > Considering the following XML fragment: > > <page name="p0" tab="products"/> > <page name="p1" tab="products"/> > <page name="p2" tab="products"/> > <page name="d" tab="downloads"/> > <page name="s" tab="support"/> > > How can I select a subset that excludes elements with a tab attribute > value matching that of a previous sibling? > > Meaning I want a list with no redundant @tab values like: > > <page name="p0" tab="products"/> > <page name="d" tab="downloads"/> > <page name="s" tab="support"/> > > Thanks, > Mike
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