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Re: [xsl] Wildcard problem

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> However the translate() funcation eliminates this differences.
> Is that possible or too complicated for XSLT? 

You just need to do the de-duplication before the translate.
eg using keys (muenchian grouping)

<xsl:key name="WAAUX" match="*[starts-with(name(),'WAAUX')]" use="name()"/>


<xsl:value-of select="count(*
[generate-id()=generate-id(key('WAAUX',name())[1])]
[starts-with(translate(name(),'123456789','000000000'),'WAAUX00')])"/>

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