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RE: [xsl] Best default value for a result tree fragment?
Subject: RE: [xsl] Best default value for a result tree fragment? From: "Nick Fitzsimons" <nick@xxxxxxxxxxxxxx> Date: Wed, 28 Sep 2005 13:49:49 +0100 (BST) |
I stand corrected on several counts :-) Thanks Michael, Nick. >> What do people think is the "best" way of specifying the >> default value for >> the parameters: >> >> <xsl:param name="contentRTF"></xsl:param> >> >> which gives a RTF containing nothing > > No: if there is no content and no select attribute, the value is a > zero-length string. You can get an RTF consisting of a document node with > no > children by writing, for example > > <xsl:param name="contentRTF"><xsl:fallback/></xsl:param> > >> >> <xsl:param name="contentRTF" select="" /> >> >> which gives an empty nodeset (or something), > > No, that's an error: the select attribute must be an XPath expression, and > this isn't > > or even >> >> <xsl:param name="contentRTF select="''" /> >> >> which gives an empty string. >> >> I appreciate that, for all practical purposes, I should get the same >> output from all of them, but was wondering which might be seen as the >> canonical way of doing it, given that any *passed* value will >> always be a >> result tree fragment. Must have my strong-typing head on today :-) >> > > I agree that logically, a document node with no children makes the most > sense. In 2.0, the cleanest way of constructing this is > > <xsl:param name="x" as="document-node()"> > <xsl:document/> > </xsl:param> > > Michael Kay > http://www.saxonica.com/
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