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[xsl] Copy path specified by parameter

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I'd like to return a sub-path which is selected by a parameter to the XSLT.
Something like:-

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0">
<xsl:param name="path" select="'/part[1]'"/> <!-- default value -->

<xsl:template match="$path">
<xsl:apply-templates mode="copy"/>
</xsl:template>
<xsl:template match="@*|node()" mode="copy">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates mode="copy"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>

What is the best way of going about this? Thanks.

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Steve Lloyd
XML Developer, Publications  group, International Baccalaureate Organization
Email: steve.lloyd[at]ibo.org
Tel:   +44 (29) 2054 7869
WWW:   http://www.ibo.org

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