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Re: [xsl] Complicated grouping and column question

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                    <xsl:apply-templates
select="/schedule/division[substring(@name,1,1) = $current-letter]">


No need to search the entire file again to find these, the divisions
with that letter are the current-group() and have already been collected
up by for-each-group.

I'd do your sorting/grouping first then split in to two later:

<xsl:template name="make-index">
<xsl:variable name="x">
	<ul>
        <xsl:for-each-group select="/schedule/division" group-by="substring(@name,1,1)">
            <xsl:sort select="current-grouping-key()" />
            <xsl:variable name="current-letter" select="current-grouping-key()" />
            
            <li>
                <h2><xsl:value-of select="$current-letter" /></h2>
                <ul>
                    <xsl:apply-templates
select="current-group()">
                        <xsl:sort select="@name" />
                    </xsl:apply-templates>
                </ul>
            </li>
        </xsl:for-each-group>
    </ul>
</xsl:variable>
<!-- the number of li's at any level with text as an approximation of line counts-->
<xsl:variable name="c" select="count($x//li[text()]) div 2"/> 

<!-- the top level (letter) li that has the half way point -->
<xsl:variable name="letter2"
                select="$x/descendent::li[$c]/ancestor::li[last()]"/>
<!-- copy the half way letter and its older siblings into one td and
the later ones into the second td.
-->
<table>
<tr>
<ul>
<xsl:copy-of select="$letter2|$letter2/preceding-sibling::li"/>
</ul>
<td>
<xsl:copy-of select="$letter2/following-sibling::li"/>
</td>
</ul>
</ul>
</tr>
</table>
</xsl:template>


Untested, but something along those lines...

David

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