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RE: [xsl] XPath query syntax

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Hi,
    Here's another variation.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl
="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

 <xsl:template match="/">

 <xsl:apply-templates select="*"/>

</xsl:template>

 <xsl:template match="br">
<xsl:text>&#xa;</xsl:text>
</xsl:template>

 <xsl:template match="text()[not(normalize-space(.) = '')]">

<line>
<xsl:value-of select="normalize-space(.)"/>
</line>

</xsl:template>
</xsl:stylesheet>

Cheers,
Omprakash.V







                    "Aron Bock"
                    <aronbock@hot        To:
xsl-list@xxxxxxxxxxxxxxxxxxxxxx
                    mail.com>            cc:     (bcc: omprakash.v/Polaris)
                                         Subject:     RE: [xsl] XPath query
syntax
                    05/19/2005
                    04:54 AM
                    Please
                    respond to
                    xsl-list






Jon, some variant of this should work.  You may also want to use
normalize-space().

<?xml version="1.0" encoding="iso8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml"/>

    <xsl:template match="/">
        <xsl:for-each select="/textarea/node()[name() != 'br']">
            <line><xsl:copy-of select="."/></line>
        </xsl:for-each>
           </xsl:template>

</xsl:stylesheet>


>From: jpk <jopaki@xxxxxxxxx>
>I have source XML:
>
><textarea>
>   line 1<br/>
>   line 2<br/>
>   line 3<br/>
>   line 4<br/>
></textarea>
>
>How do I query for each of the line texts?  That is, I
>need to get each text [node] that preceeds all <br>
>tags.

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