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I need to do a transformation that will take an input xml string in a format that is something like
...<a>1</a><a>2</a><a>3</a><a>4</a>...
and apart from transforming it, will split the multiple node occurrences for "a" into different xml's i.e.
xml[1]=<a>1</a>
xml[2]=<a>2</a>...
I was thnking that if xsl offers some kind of looping facility, that may help. But then xsl transformation presumably being single-input, single-output process, just an xsl maynot by itself suffice. Is there a possibility that somehow I can have a java loop pass a looping variable into the xsl-sheet, so that the first transformation gives me the first occurrence of "a", and so on.
Another approach could be to let the xsl transformation return a single xml that has the multiple "a" occurrences and then subsequently seperate them out by carrying out XPath/DOM operations on the transformed xml.
- Vishwajit.
[xsl] Splitting multiple node occurrences into separate xmls
Subject: [xsl] Splitting multiple node occurrences into separate xmls From: "Vishwajit Pantvaidya" <pantvaidya@xxxxxxxxxxx> Date: Thu, 28 Apr 2005 12:58:01 -0700 |
I need to do a transformation that will take an input xml string in a format that is something like
...<a>1</a><a>2</a><a>3</a><a>4</a>...
and apart from transforming it, will split the multiple node occurrences for "a" into different xml's i.e.
xml[1]=<a>1</a>
xml[2]=<a>2</a>...
I was thnking that if xsl offers some kind of looping facility, that may help. But then xsl transformation presumably being single-input, single-output process, just an xsl maynot by itself suffice. Is there a possibility that somehow I can have a java loop pass a looping variable into the xsl-sheet, so that the first transformation gives me the first occurrence of "a", and so on.
Another approach could be to let the xsl transformation return a single xml that has the multiple "a" occurrences and then subsequently seperate them out by carrying out XPath/DOM operations on the transformed xml.
- Vishwajit.
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