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RE: [xsl] namespaces in xslt
Subject: RE: [xsl] namespaces in xslt From: omprakash.v@xxxxxxxxxxxxx Date: Fri, 1 Apr 2005 17:46:16 +0530 |
Hi, By "detailed navigational expressions" if you mean using indices like [1], [2] etc in my xpath, I was only using it bcos I could be sure that <root> will have a child named <tr> and <tr>, a child named <slideshow> (just now realized). However, I will try to follow your advise in future. Cheers, Omprakash.V "Michael Kay" <mike@saxonic To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx> a.com> cc: (bcc: omprakash.v/Polaris) Subject: RE: [xsl] namespaces in xslt 04/01/2005 05:35 PM Please respond to xsl-list Your root element has only one child, it is a <tr> element. So root/*[2] selects nothing. The <slideshow> is a child of the <tr>. You seem to be trying to write detailed navigational expressions to reach specific nodes in your source document. This isn't very robust, you will have to make lots of changes when the source changes. It's much better to write template rules to process each kind of element, and then recurse down the tree using xsl:apply-templates. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: omprakash.v@xxxxxxxxxxxxx [mailto:omprakash.v@xxxxxxxxxxxxx] > Sent: 01 April 2005 12:54 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] namespaces in xslt > > > Hi, > Iam having diffculty following what's happening: > > I have xml like this > > <table> > <th> > <root> > <tr> > <slideshow xmlns="urn:hl7-org/v3" title="Sample Slide Show" > date="Date of > publication" author="Yours Truly"> > <td><a href="file:///N65538"/> > </td> > </slideshow> > </tr> > </root> > </th> > </table> > > > And my xsl: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet version="1.0" xmlns:xsl > ="http://www.w3.org/1999/XSL/Transform" xmlns="urn:hl7-org/v3" > > > <xsl:output method="xml" indent="yes" /> > > <xsl:template match="/"> > > <xsl:for-each select="//root/*[1]"> > <xsl:copy> > <xsl:copy-of select="@*"/> > <xsl:apply-templates select="@*|node()"> > <xsl:with-param name="rootnode" select="$rootnode"/> > </xsl:apply-templates> > </xsl:copy> > </xsl:for-each> > </xsl:template> > > </xsl:stylesheet> > > > When I select //own:root/*[1] in the <xsl:for-each>, I get > the following > > <?xml version="1.0" encoding="UTF-8"?> > <tr xmlns="http://XYZ"/> > > but when I make it //root/*[2], I get nothing. But if you see, the > slideshow is really at position 2 so I need to use 2. > > > Cheers, > Omprakash.V > > > > > > > > > > > > > > > > > > > > > This e-Mail may contain proprietary and confidential > information and is sent for the intended recipient(s) only. > If by an addressing or transmission error this mail has been > misdirected to you, you are requested to delete this mail immediately. > You are also hereby notified that any use, any form of > reproduction, dissemination, copying, disclosure, modification, > distribution and/or publication of this e-mail message, > contents or its attachment other than by its intended > recipient/s is strictly prohibited. > > Visit Us at http://www.polaris.co.in This e-Mail may contain proprietary and confidential information and is sent for the intended recipient(s) only. If by an addressing or transmission error this mail has been misdirected to you, you are requested to delete this mail immediately. You are also hereby notified that any use, any form of reproduction, dissemination, copying, disclosure, modification, distribution and/or publication of this e-mail message, contents or its attachment other than by its intended recipient/s is strictly prohibited. Visit Us at http://www.polaris.co.in
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RE: [xsl] (newby) extraction of CDA, Michael Kay | Date | Re: [xsl] namespaces in xslt, David Carlisle |
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