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Re: [xsl] question about filling of nodeset


Subject: Re: [xsl] question about filling of nodeset
From: David Carlisle <davidc@xxxxxxxxx>
Date: Thu, 17 Mar 2005 15:37:43 GMT

  Now I have this code

  <xsl:variable name="AllKatern">
   <xsl:for-each select="/HowardsHome/Katern">
  
    <xsl:copy-of select="."/>
   </xsl:for-each>
  </xsl:variable>
  <xsl:variable name="AllKaternNodes"
  select="msxml:node-set($AllKatern)"/>

that's quite an expensive operation as you have to copy everthing and
also requires the node-set extension

 <xsl:variable name="AllKaternNodes" select="/HowardsHome/Katern"/>

Is a lot less to type and a _lot_ more efficient and just saves the node
set directly, which is almost certainly what you want here.


  Here I have a copy of everything but now I want the <title> of each
  Article with replaced quotes single double etc. That's not the problem,
  but how can I write the result of this back to the nodeset?

You can never "write back" to anything in xslt, the transformation model
is always that you take a source tree and generate a new result tree.
So in your case you would apply som etemplates to $AllKaternNodes
and get a new tree, then do with it whatever you need to do
either letting it go to the main result tree, or saving it in a
variable.



David

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