Re: [xsl] Newbie question - Muenchian method and XPath

> So it's dragging all <item>s together (as xsl:key is obviously document wide 
> and I can't use scope)., which isn't what I want! (I want:

I think Jeni has an example (the archives of this list will have lots:-)
but basically you just need to make sure that the key has a different
value for each different group, so if children of group are to be
grouped separately include that in the key

<xsl:key name="x" match="item" use="concat(../@value,':',@name)"/>

and use a similar concat in the call to key() so your first group is all
items which have a key of 1:a for example which should just return apple
and banana.

David

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