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[xsl] Get nodes with document() and applying templates to them

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Hi again:

I'm trying to do something like this:

Given

<Menu>
	<Menu_K>X00123</Menu_K>
	<MenuData/>
	<MenuTipo>TXT</MenuTipo>
	<MenuTitulo>Ambitos</MenuTitulo>
	<Menu>
		<Menu_K>X00124</Menu_K>
		<MenuData>X00125</MenuData>
		<MenuTipo>REP</MenuTipo>
		<MenuTitulo>(...)</MenuTitulo>
	</Menu>
</Menu>

and another XML similar (actually it can be the same)

<Menu>
	<Menu_K>X00125</Menu_K>
	<MenuData/>
	<MenuTipo>TXT</MenuTipo>
	<MenuTitulo>Sub-Ambitos</MenuTitulo>
	<Menu>
		<Menu_K>X00126</Menu_K>
		<MenuData/>
		<MenuTipo>TXT</MenuTipo>
		<MenuTitulo>Sub-Sub-Ambitos</MenuTitulo>
	</Menu>
</Menu>

i want to apply a identity transform that simply replaces the REP
menus with the menu whose K is defined on MenuData, so in the example
i'll get


<Menu>
	<Menu_K>X00123</Menu_K>
	<MenuData/>
	<MenuTipo>TXT</MenuTipo>
	<MenuTitulo>Ambitos</MenuTitulo>
	<Menu>
		<Menu_K>X00125</Menu_K>
		<MenuData/>
		<MenuTipo>TXT</MenuTipo>
		<MenuTitulo>Sub-Ambitos</MenuTitulo>
		<Menu>
			<Menu_K>X00126</Menu_K>
			<MenuData/>
			<MenuTipo>TXT</MenuTipo>
			<MenuTitulo>Sub-Sub-Ambitos</MenuTitulo>
		</Menu>
	</Menu>
</Menu>

I've done this

	<xsl:template match="Menu">
		<xsl:choose>
			<xsl:when test="MenuTipo='REP'">

				<xsl:apply-templates
select="document('TreeMenu.xml')//Menu[Menu_K=current()/MenuData]/Menu"
/>

			</xsl:when>
			<xsl:otherwise>
				<xsl:copy>
					<xsl:apply-templates select="*"/>
				</xsl:copy>
			</xsl:otherwise>
		</xsl:choose>
	</xsl:template>

wich is working OK, *unless* in the second XML i have also REP menus.
In that case the REP menus on the second tree are just ignored, nor
are copyed nor REPlaced.

What i was hoping to get is the replaced menus, everywere. That is why
i'm using apply-templates instead of copy-of, tath copys the entire
second tree but withou replacing the REP's.

What am i doing wrong in here?

Thanks.

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