[XSL-LIST Mailing List Archive Home] [By Thread] [By Date]

[xsl] Select and display a node

---

---

Hi all,

Sorry for this newbie issue, but I was not able to find any suitable solution
so far.

I have an xml looking like that:

<rss>
	<channel>
		<item id="24874">
			<title>News 1</title>
			<page id="456">
			<pageNumber>1</pageNumber>
				<layout>1</layout>
				<title>qsdqsd</title>
				<date />
			</page>
			<page id="457">
				<pageNumber>1</pageNumber>
				<layout>1</layout>
				<title>qsdqsd</title>
				<date />
			</page>
		</item>
	</channel>
</rss>



I have a XSL document that will display a page detail (the page id being a
param)

I have tried the following:

<xsl:template match="rss/channel" >
<xsl:for-each select="item/page[@id=456]">
	id = <xsl:value-of select="@id"/>
</xsl:for-each>
</xsl/template>

But when I run this, I get "id = 456" twice..


Any suggestion welcome

Thanx,

seb

---