[XSL-LIST Mailing List Archive Home]
[By Thread]
[By Date]
[xsl] How to retrieve value(which is copied into RTF as a variable) from RTF
Subject: [xsl] How to retrieve value(which is copied into RTF as a variable) from RTF From: "Ranjan K. Baisak" <ranjanbaisak@xxxxxxxxx> Date: Tue, 4 Jan 2005 05:19:53 -0800 (PST) |
I have a RTF with following declaration <xsl:variable name="professionLevel"> <xsl:for-each select="//profession"> <xsl:variable name="nameval" select="@name"/> <xsl:variable name="parentval" select="@parent"/> <xsl:for-each select="exslt:node-set($leverreference)/*"> <xsl:variable name="referid" select="@levelref"/> <xsl:if test="$referid=$parentval"> <xsl:copy> <xsl:copy-of select="$nameval"/> </xsl:copy> </xsl:if> </xsl:for-each> </xsl:for-each> </xsl:variable> Later I want to retrieve $nameval from professionLevel RTF. I tried with <xsl:for-each select="exslt:node-set($professionLevel)/*"> <xsl:value-of select="."/> </xsl:for-each> but it did not work. Any suggestion? regards, Ranjan __________________________________ Do you Yahoo!? Send holiday email and support a worthy cause. Do good. http://celebrity.mail.yahoo.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
RE: [xsl] How to call extension fun, Manpreet Singh | Thread | RE: [xsl] How to retrieve value(whi, Michael Kay |
RE: [xsl] How to call extension fun, Michael Kay | Date | [xsl] How to retrieve value(which i, Ranjan K. Baisak |
Month |