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RE: [xsl] Simple XML to XML transformation question
Subject: RE: [xsl] Simple XML to XML transformation question From: "Joe Heidenreich" <HeidenreichJ@xxxxxxxx> Date: Wed, 17 Nov 2004 13:23:16 -0500 |
You are calling a specific template "Car" but you never defined it. I'm also not sure what "cd" is, but since you don't have any "cd" elements you won't match them. It should be matching on "Car". <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="Data"> <Car><xsl:apply-templates/></Car> </xsl:template> <xsl:template match="Car"> <Model><xsl:apply-templates/></Model> </xsl:template> </xsl:stylesheet> I think that should do the trick. -Joe -----Original Message----- From: Nick Roberts [mailto:nick_roberts5@xxxxxxxxxxx] Sent: Wednesday, November 17, 2004 1:06 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Simple XML to XML transformation question Hi, I'm basically trying to modify the name of root node element... with the following XML file... <?xml-stylesheet type="text/xsl" href="renewal.xsl"?> <Data> <car>Chevy</car> <car>Dodge</car> <car>Ford</car> </Data> How could I change the <Data> element to <Car> and the <Car> tags to <Model> My initial attempt at an XSL file was as follows... <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="iso-8859-1" indent="yes"/> <xsl:template match="Data"> <Car> <xsl:apply-templates select="Car"/> </Car> </xsl:template> <xsl:template match="cd"> <Model> </Model> </template> </xsl:stylesheet> Is seems to output a blank page?? Any ideas guys? Cheers, Nick
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