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Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method?
Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method? From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 7 Oct 2004 15:57:09 +0100 |
How can I implement filtering for two keywords, that is display all that have either "food" or "drink". as I said. you need to make $info have a node set consisting of nodes with values food and drink You may be able to pass in a node set directly from your API (you can in msxml, passing in a dom node list if I recall) Otherwise you'll have to generate the nodeset from a result tree fragment or an external document inside a stylesheet you could do it using xx:node-set or document('') eg <xsl:variable name="info"> <x>food</x> <x>drink</x> </xsl:variable> <xsl:variable name="info-nodeset" select="document('')/*/xsl:variable[@name='info']"/> then $info-nodeset is a node set of two nodes with values food and drink and @filter=$info-nodeset will therefore be true if filter attribute is food or drink and false otherwise. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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