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Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method?
Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method? From: David Carlisle <davidc@xxxxxxxxx> Date: Tue, 5 Oct 2004 15:08:46 +0100 |
[going back on list] > As I said, I am unable to use as posted I get: $ saxon filter.xml filter.xsl Error at xsl:for-each on line 17 of file:/c:/tmp/filter.xsl: Key 'by-info' has not been defined Transformation failed: Run-time errors were reported taking <xsl:key name="by-info" match="Article" use="@info"/> from an earlier post and adding it after xsl:stylesheet, I get: $ saxon filter.xml filter.xsl <?xml version="1.0" encoding="utf-8"?> <Documents> <Document name="sub"> <Article title="1.1" info="sub" filter="food"/> </Document> <Document name="main"> <Article title="2.2" info="main" filter="food"/> </Document> </Documents> That is, apart from droping your key definintion, the code you posted works as expected. So if you really get "Exception Details: System.NullReferenceException: Object reference not set to an instance of an object." in myXslTrans.Transform(myXPathDoc, null, writer, null); looks like a bug in your processor (Microsoft .net implementation?) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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