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Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method?

Subject: Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method?
From: Anton Triest <anton@xxxxxxxx>
Date: Wed, 29 Sep 2004 22:34:01 +0200

Hi Michael,

Sorry, I was too quick in suggesting to add the filtering test to the grouping predicate:

<xsl:for-each select="Document/Article
  [count(.|key('by-info', @info)[1])=1 and (@filter='food')]">


That worked with my sample input, but more out of coincidence.
The filter test actually belongs in the next statement:

<xsl:template match="Documents"> <Documents> <xsl:for-each select="Document/Article[count(.|key('by-info', @info)[1])=1]"> <Document name="{@info}"> <xsl:copy-of select="key('by-info', @info)[@filter='food']"/> </Document> </xsl:for-each> </Documents> </xsl:template>

Hope that helps better :)

Anton

Current Thread
Re: [xsl] Re: [xslt transform & grouping] Using the Muenchian Method?, (continued) Michael PG - 29 Sep 2004 08:00:26 -0000 Anton Triest - 29 Sep 2004 13:17:55 -0000 Michael PG - 29 Sep 2004 11:41:51 -0000 Michael PG - 29 Sep 2004 19:45:38 -0000 Anton Triest - 29 Sep 2004 20:34:22 -0000 <= Michael PG - 29 Sep 2004 21:03:28 -0000 Anton Triest - 30 Sep 2004 07:01:12 -0000

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